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w^2+9w-136=0
a = 1; b = 9; c = -136;
Δ = b2-4ac
Δ = 92-4·1·(-136)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-25}{2*1}=\frac{-34}{2} =-17 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+25}{2*1}=\frac{16}{2} =8 $
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